update: finalize conditions and formulas transposition

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2026-06-28 20:23:54 +02:00
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@@ -600,6 +600,69 @@ m-\prod_{l=2}^kd_l&= -\prod_{l=2}^kd_l+ (d_3-1-i_3)\prod_{s=4}d_s+\sum_{j=4}^k(d
\end{align*}
\subsection{formulas}
$$m=\sum_{j=1}^ki_j\prod_{l=j+1}^kd_l$$
if $i_1<d_1-1$
\begin{align*}
m'&=m+\prod_{l=2}^kd_l \\
&=(i_1+1)\prod_{l=2}^kd_l+\sum_{j=2}^ki_j\prod_{l=j+1}d_l
\end{align*}
if $i_1=d_1-1$ and $i_2<d_2-1$
\begin{align*}
m'&=m-(d_1-1)\prod_{l=2}^kd_l + \prod_{l=3}^kd_l \\
&=0\prod_{l=2}^k d_l+(i_2+1)\prod_{l=3}^k d_l+\sum_{j=3}^ki_j\prod_{l=j+1}d_l
\end{align*}
if $i_1=d_1-1$ and $i_2=d_2-1$ and $i_3<d_3-1$
\begin{align*}
m'&=m-(d_1-1)\prod_{l=2}^kd_l-(d_2-1)\prod_{l=3}^kd_l + \prod_{l=4}^kd_l \\
&=0\prod_{l=2}^k d_l+0\prod_{l=3}^k d_l+(i_3+1)\prod_{l=4}^k d_l+\sum_{j=4}^ki_j\prod_{l=j+1}d_l
\end{align*}
if $i_1=d_1-1$ and $i_2=d_2-1$ and $i_3=d_3-1$ and $i_4<d_4-1$
\begin{align*}
m'&=m-(d_1-1)\prod_{l=2}^kd_l-(d_2-1)\prod_{l=3}^kd_l -(d_3-1)\prod_{l=4}^kd_l + \prod_{l=5}^kd_l \\
&=0\prod_{l=2}^k d_l+0\prod_{l=3}^k d_l+0\prod_{l=4}^k d_l+(i_4+1)\prod_{l=5}^k d_l+\sum_{j=5}^ki_j\prod_{l=j+1}d_l
\end{align*}
and so on!!
\subsection{conditions}
if $i_1<d_1-1$
\begin{align*}
m'&=m+\prod_{l=2}^kd_l \\
&=(i_1+1)\prod_{l=2}^kd_l+\sum_{j=2}^ki_j\prod_{l=j+1}d_l\\
&\le\prod_{l=1}d_l-1
\end{align*}
if $i_1=d_1-1$ and $i_2<d_2-1$
\begin{align*}
m+\prod_{l=2}^kd_l &= \prod_{l=1}^kd_l+\sum_{j=2}^ki_j\prod_{l=j+1}^kd_l\\
&\ge \prod_{l=1}^kd_l \\
m'&=m-(d_1-1)\prod_{l=2}^kd_l + \prod_{l=3}^kd_l \\
&=0\prod_{l=2}^k d_l+(i_2+1)\prod_{l=3}^k d_l+\sum_{j=3}^ki_j\prod_{l=j+1}d_l \\
& \le \prod_{l=2}^kd_l-1
\end{align*}
if $i_1=d_1-1$ and $i_2=d_2-1$ and $i_3<d_3-1$
\begin{align*}
m+\prod_{l=2}^kd_l & \ge \prod_{l=1}^kd_l-1 \\
m-(d_1-1)\prod_{l=2}^kd_l + \prod_{l=3}^kd_l &= \prod_{l=2}^kd_l + \sum_{j=3}^ki_j\prod_{l=j+1}^kd_l \\
& \ge \prod_{l=2}^kd_l \\
m'&=m-(d_1-1)\prod_{l=2}^kd_l-(d_2-1)\prod_{l=3}^kd_l + \prod_{l=4}^kd_l \\
&=0\prod_{l=2}^k d_l+0\prod_{l=3}^k d_l+(i_3+1)\prod_{l=4}^k d_l+\sum_{j=4}^ki_j\prod_{l=j+1}d_l\\
& \le \prod_{l=3}d_l-1
\end{align*}
if $i_1=d_1-1$ and $i_2=d_2-1$ and $i_3=d_3-1$ and $i_4<d_4-1$
\begin{align*}
m+\prod_{l=2}^kd_l & \ge \prod_{l=1}^kd_l-1 \\
m-(d_1-1)\prod_{l=2}^kd_l + \prod_{l=3}^kd_l &= \prod_{l=2}^kd_l + \sum_{j=3}^ki_j\prod_{l=j+1}^kd_l \\
& \ge \prod_{l=2}^kd_l \\
m-(d_1-1)\prod_{l=2}^kd_l -(d_2-1)\prod_{l=3}^kd_l + \prod_{l=4}^kd_l &= \prod_{l=3}^kd_l + \sum_{j=4}^ki_j\prod_{l=j+1}^kd_l \\
& \ge \prod_{l=3}^kd_l \\
m'&=m-(d_1-1)\prod_{l=2}^kd_l-(d_2-1)\prod_{l=3}^kd_l -(d_3-1)\prod_{l=4}^kd_l + \prod_{l=5}^kd_l \\
&=0\prod_{l=2}^k d_l+0\prod_{l=3}^k d_l+0\prod_{l=4}^k d_l+(i_4+1)\prod_{l=5}^k d_l+\sum_{j=5}^ki_j\prod_{l=j+1}d_l\\
&\le \prod_{l=4}d_l-1
\end{align*}